Question
Mathematics Question on What is Factorisation?
Factorise the following expressions
- 7x−42
- 6p−12q
- 7a2+14a
- −16z+20z3
- 20l2m+30alm
- 5x2y−15xy2
- 10a2−15b2+20c2
- −4a2+4ab−4ca
- x2yz+xy2z+xyz2
- ax2y+bxy2+cxyz
(i) 7x=7×x
42=2×3×7
The common factor is 7.
∴ 7x−42=(7×x)−(2×3×7)=7(x−6)
(ii) 6p=2×3×p
12q=2×2×3×q
The common factors are 2 and 3.
∴ 6p−12q=(2×3×p)−(2×2×3×q)
= 2×3[p−(2×q)]
= 6(p−2q)
(iii) 7a2=7×a×a
14a=2×7×a
The common factors are 7 and a.
∴ 7a2+14a=(7×a×a)+(2×7×a)
= 7×a[a+2]=7a(a+2)
(iv) 16z=2×2×2×2×z
20z3=2×2×5×z×z×z
The common factors are 2, 2, and z.
∴ −16z+20z3=−(2×2×2×2×z)+(2×2×5×z×z×z)
= (2×2×z)[−(2×2)+(5×z×z)]
= 4z(−4+5z2)
(v) 20l2m=2×2×5×l×l×m
30alm=2×3×5×a×l×m
The common factors are 2,5, l, and m.
∴ 20l2m+30alm=(2×2×5×l×l×m)+(2×3×5×a×l×m)
= (2×5×l×m)[(2×l)+(3×a)]
= 10lm(2l+3a)
(vi) 5x2y=5×x×x×y
15xy2=3×5×x×y×y
The common factors are 5, x, and y.
∴ 5x2y−15xy2
= (5×x×x×y)−(3×5×x×y×y)
= 5×x×y[x−(3×y)]
= 5xy(x−3y)
(vii) 10a2=2×5×a×a
15b2=3×5×b×b
20c2=2×2×5×c×c
The common factor is 5.
10a2−15b2+20c2
= (2×5×a×a)−(3×5×b×b)+(2×2×5×c×c)
= 5[(2×a×a)−(3×b×b)+(2×2×c×c)]
= 5(2a2−3b2+4c2)
(viii) 4a2=2×2×a×a
4ab=2×2×a×b
4ca=2×2×c×a
The common factors are 2,2, and a.
∴ −4a2+4ab−4ca=−(2×2×a×a)+(2×2×a×b)−(2×2×c×a)
=2×2×a[−(a)+b−c]
= 4a(−a+b−c)
(ix) x2yz=x×x×y×z
xy2z=x×y×y×z
xyz2=x×y×z×z
The common factors are x,y, and z.
∴ x2yz+xy2z+xyz2
= (x×x×y×z)+(x×y×y×z)+(x×y×z×z)
= x×y×z[x+y+z]
= xyz(x+y+z)
(x) ax2y=a×x×x×y
bxy2=b×x×y×y
cxyz=c×x×y×z
The common factors are x and y.