Question
Mathematics Question on Trigonometric Functions
f(x)=x3−3x+5 then f(sin23π)+f(cos23π)=
A
10
B
12
C
14
D
16
Answer
12
Explanation
Solution
sin323π−3sin23π+5+cos323π+5 = −1+3+5+0−0+5=12
f(x)=x3−3x+5 then f(sin23π)+f(cos23π)=
10
12
14
16
12
sin323π−3sin23π+5+cos323π+5 = −1+3+5+0−0+5=12