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Question

Mathematics Question on Trigonometric Functions

f(x)=x33x+5f(x)=x^3 - 3x + 5 then f(sin3π2)+f(cos3π2)=f \left( \sin \frac{3 \pi }{ 2} \right) + f \left( \cos \frac{3 \pi}{2} \right) =

A

10

B

12

C

14

D

16

Answer

12

Explanation

Solution

sin33π23sin3π2+5+cos33π2+5\sin^{3} \frac{3\pi}{2 } -3 \sin \frac{3\pi}{2} +5 + \cos^{3} \frac{3\pi}{2 }+5 = 1+3+5+00+5=12-1 + 3 + 5 + 0 - 0 + 5 = 12