(f(x)=\frac{2x^2-3x+8}{2x^2+3x+8}), Then sum of maximum and... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

$f(x)=\frac{2x^2-3x+8}{2x^2+3x+8}$ , Then sum of maximum and minimum values of f(x) is:

A

$\frac{136}{55}$

B

$\frac{146}{55}$

C

$\frac{146}{11}$

D

$\frac{136}{11}$

Answer

$\frac{146}{55}$

Explanation

Solution

The correct answer is option (B): $\frac{146}{55}$