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Question: f three sets are given as \(A=\left\\{ x:x\in W,3\le x\le 6 \right\\},B=\\{3,5,7\\}\) and \(C=\\{2,4...

f three sets are given as A=\left\\{ x:x\in W,3\le x\le 6 \right\\},B=\\{3,5,7\\} and C=2,4C=\\{2,4\\} ; then find: BCB-C .

Explanation

Solution

Hint: The given question is related to set operations and notation of a set in set-builder form. Try to recall the different operations of sets, such as the difference of two sets, the complement of a set, intersection of two sets, etc.

Before proceeding with the solution, we must know the concept of set operations and set notations. The set operation that is to be used while solving the question is the difference of two sets and the set notation used is the set-builder notation.
The set-builder notation is a notation in which the set is described by using the properties of the elements.
For example: Consider the set B=2,4,6,8,10B=\\{2,4,6,8,10\\}. Here BB is a set of elements that are positive and even numbers less than 1212. So, the property of the elements of the set is that they are positive even numbers less than 1212. So, the set BBis represented in the set-builder form as B=x:xispositiveevennumber<12B=\\{x:x\,is\,positive\,even\,number\,<12\\} .
Now, the set AA is given as A=\left\\{ x:x\in W,3\le x\le 6 \right\\}. We can see that the property of the elements of the set AA is that they are whole numbers that are greater than or equal to 33 and less than or equal to 66. So, the set AA can be written as A=3,4,5,6A=\\{3,4,5,6\\}.
Now, we will consider two sets AA and BB such that the set AA is given as A=a,b,c,d,eA=\\{a,b,c,d,e\\} , and the set BB is given as B=d,e,f,gB=\\{d,e,f,g\\}. The difference of the two sets AA and BB is the set of all such elements, which are present in the setAA but not in the set BB . It is written as ABA-B and is given as AB=a,b,cA-B=\\{a,b,c\\}.
Now, we are asked to find the value of BCB-C , where the set BB is given as B=3,5,7B=\\{3,5,7\\} and, the set CC is given as C=2,4C=\\{2,4\\}. We can see that all the elements in the set BB are not present in the set CC.
So, the value of BCB-C is given as BC=3,5,7B-C=\\{3,5,7\\}.

Note: The set builder form is read as “AA is the set of all xx such that xx is a natural number less than 77.” Students generally get confused between set builder notation of sets and roster notation of sets. Both are different and hence, should not be confused. This confusion can lead to wrong answers. Also, while evaluating the difference of two sets, make sure to mention the elements which are present in the first set and not in the second set. Most of the students mention the elements that are present in the second set and not in the first set, which is wrong. Such mistakes should be avoided.