Question
Question: f : R →\(\left( 0 , \frac { \pi } { 2 } \right]\)where f(x) = cot<sup>-1</sup> (x<sup>2</sup> + x + ...
f : R →(0,2π]where f(x) = cot-1 (x2 + x + a). Complete set of values of 'a' such that f(x) is onto is
A
[43,∞)
B
[1, ∞)
C
[21,∞)
D
[41,∞)
Answer
[41,∞)
Explanation
Solution
We know that cot-1(x) ∈(0, π/2] ∀ x > 0. Thus x2 + x + a ≥ 0 ∀ x ∈ R
⇒ 1 - 4a ≤ 0 ⇒ a≥41