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Question

Question: f f(x) = sin<sup>–1</sup>\(\frac { - 1 } { 2 }\)£ x £ 1 then f(x) =...

f f(x) = sin–112\frac { - 1 } { 2 }£ x £ 1 then f(x) =

A

sin–112\frac { 1 } { 2 }– sin–1x

B

sin–1x – π6\frac { \pi } { 6 }

C

sin–1x + π6\frac { \pi } { 6 }

D

None of these

Answer

sin–1x – π6\frac { \pi } { 6 }

Explanation

Solution

f(x) = sin–1(sin(θπ6))\left( \sin \left( \theta - \frac { \pi } { 6 } \right) \right) (when x = sinq)

q – p/6 Ž sin–1x–p/6