Question

Expression for an electric field is given by $\overrightarrow{ E }=4000 x^2 i \frac{ V }{ m }$ The electric flux through the cube of side $20 cm$ when placed in electric field (as shown in the figure) is ___$V cm$

Answer 1

The correct answer is 640
Flux $=\vec{E}⋅\vec{A}$
$=4000(0⋅2)^2\frac{V}{m}​⋅(0⋅2)^2m^2$
=4000×16×10−4Vm
=640 Vcm