Question
Question: Express the following in the form of \(a + ib\), \(a,b \in R\), \(i = \sqrt { - 1} \). State the val...
Express the following in the form of a+ib, a,b∈R, i=−1. State the values of a and b.
(1+2i)(−2+i)
Solution
In this question, we are given an equation and we have been asked to write it in the form of a=ib and also, we have to state the values of a and b. We will start by multiplying the brackets of the given equation just like we multiply the other normal equations (a+b)(c+d). After multiplying, we will rearrange the resultant equation by grouping the like terms and performing the addition, subtraction on them. After that, we will compare the final equation with a+ib. This will give us the values of a and b.
Complete step-by-step solution:
We are given an equation (1+2i)(−2+i) and we have to express it in the form of a=ib and also, we have to state the values of a and b.
We will start with multiplying the brackets,
⇒(1+2i)(−2+i)
On multiplying we will get,
⇒(−2+i−4i+2i2)
We know that i=−1. Therefore, if we square both the sides, we will get i2=−1. Putting in the above equation,
⇒(−2+i−4i+2(−1))
On rearranging and simplifying we will get,
⇒((−2−2)+(i−4i))
Simplifying further,
⇒−4−3i
Now, we have to state the values of a and b.
Comparing the equation a+ib, we will get, a=−4 and b=−3.
∴ a=−4 and b=−3.
Note: 1) The equations we dealt with in this question are called complex equations because it includes ′i′. The ′i′ is an imaginary number as it cannot be located on the number line.
2) The value of ′i′ is −1. We have to understand the powers of ′i′.
⇒i2=−1,
⇒i3=i2∗i=−i,
And finally, i4=1. These help in solving problems related to complex equations.