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Question

Mathematics Question on Real Numbers and their Decimal Expansions

Express the following in the form pq\frac{p }{ q} , where p and q are integers and q ≠ 0.

(i) 0.6(ii) 0.47 (iii) 0.001.

Answer

(i) 0.6\overline{0.6} = 0.666....

One digit 6 is repeating. We multiply it with 10 on both sides.

10x = 6.6\overline{6.6} ⇒ 10x = 6 + x

⇒ 10x - x = 6 ⇒ 9x = 6 ⇒ x = 69\frac{6}{9} = 23\frac{2}{3}

(ii) 0.47\overline{0.47}= 0.4777....

One digit is repeating. We multiply it with 10 on both sides.

∴ 10x = 4.7= 4.3 + .47 = 4.3 + x

⇒ 9x = 4.3 ⇒ x = 4.39\frac{4.3}{9} =4390\frac{43}{90}

(iii) 0.001= x = 0.001

Here three digits repeats; we multiply with 1000.

∴ 1000x = 1.001\overline{1.001}= 1000x = 1 + x

⇒ 1000x - x = 1 ⇒ 999x = 1

⇒ x = 1999\frac{1}{999}