Solveeit Logo
Login

Question

Question: Express mass of \(6.022 \times {10^{22}}\) molecules of \(C{O_2}\) in grams....

Express mass of 6.022×10226.022 \times {10^{22}} molecules of CO2C{O_2} in grams.

Explanation

Solution

Carbon dioxide is a type of hetero atomic molecule because it consist of more than one type of atoms. Since carbon dioxide has a total of three atoms it is also known as a triatomic molecule.
The number 6.022×10236.022 \times {10^{23}} is known as the Avogadro number.

Complete answer:
One mole of any compound contains a total number of molecules equal to Avogadro number.
Hence, 11 mole of CO2C{O_2} contains a total number of 6.022×10236.022 \times {10^{23}} particles or molecules.
Molecular weight of 11 mole of CO2C{O_2} is equal to the sum of atomic mass of carbon and oxygen.
Atomic weight of (C)\left( C \right) is 12g12g
Atomic weight of (O)\left( O \right) is 16g16g
M=12+2×16gM = 12 + 2 \times 16g
After solving we get, Molecular weight of 11 mole of CO2C{O_2} is =44g = 44g
As we know that each mole of carbon dioxide contains 6.022×10236.022 \times {10^{23}} molecules so, 44g44g of carbon dioxide also contains the same amount of molecules.
Mass of 6.022×10236.022 \times {10^{23}} particles of CO2C{O_2} in grams is equal to its molecular mass in grams i.e.(44g)\left( {44g} \right)
11 mole of CO2C{O_2} =6.022×1023 = 6.022 \times {10^{23}} molecules of CO2C{O_2} =44g = 44g of CO2C{O_2}
Hence, 11 molecule of CO2C{O_2} weigh =446.022×1023g = \dfrac{{44}}{{6.022 \times {{10}^{23}}}}g of CO2C{O_2}
So 6.022×10226.022 \times {10^{22}} molecule of CO2C{O_2} weigh =446.022×1023×6.022×1022g = \dfrac{{44}}{{6.022 \times {{10}^{23}}}} \times 6.022 \times {10^{22}}g of CO2C{O_2}
After solving the above equation we get,
6.022×10226.022 \times {10^{22}}molecule of CO2C{O_2} weigh =44×0.1g = 44 \times 0.1g of CO2C{O_2}
6.022×10226.022 \times {10^{22}} molecule of CO2C{O_2} weigh =4.4g = 4.4g of CO2C{O_2}
Hence, weight of 6.022×10226.022 \times {10^{22}} molecule of CO2C{O_2} is 4.4g4.4g

Note:
Avogadro number remains the same for one mole of any atom. It is alphabetically represented as NA{N_A}.
Do not forget to consider the atomic mass of every constituting atom in units of grams.
CO2(g)C{O_{2\left( g \right)}} Is a major responsible gas for causing global warming and it also gets converted into carbonic acid which is a component of acid rain.