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Question: Express dielectric constant of a medium in terms of capacitance. What is its SI unit?...

Express dielectric constant of a medium in terms of capacitance. What is its SI unit?

Explanation

Solution

Capacitance is described as the property to hold charge. Capacitance is dependent on the geometry of the capacitor.
The mathematical expression for a parallel plate capacitor is C0=Aε0d{C_0} = \dfrac{{A{\varepsilon _0}}}{d} where C is the capacitance, A is the area of cross section of the capacitor, d is the separation between the plates and ε0{\varepsilon _0} is the permeability of free space. This is the expression for the capacitor with no dielectric in between.
When a dielectric of dielectric constant K is present between the plates, the capacitance is given by Ck=KAε0d{C_k} = \dfrac{{KA{\varepsilon _0}}}{d}.
The dielectric constant is the ratio of permeability of a material to the permeability of free space.

Complete step by step solution:
We know that the dielectric constant is the ratio of permeability of a material to the permeability of free space. The expression is given as K=εrε0K = \dfrac{{{\varepsilon _r}}}{{{\varepsilon _0}}} .
Let the capacitance in a dielectric medium be Cr{C_r} . Its value is given by Cr=Aεrd{C_r} = \dfrac{{A{\varepsilon _r}}}{d} which simplifies to Cr=KAε0d{C_r} = \dfrac{{KA{\varepsilon _0}}}{d} .
But we know that the value of capacitance with the same geometry but in free space will be C0=Aε0d{C_0} = \dfrac{{A{\varepsilon _0}}}{d} .
Taking the ratio of Cr{C_r} and C0{C_0} ,
CrC0=KAε0dAε0d\dfrac{{{C_r}}}{{{C_0}}} = \dfrac{{\dfrac{{KA{\varepsilon _0}}}{d}}}{{\dfrac{{A{\varepsilon _0}}}{d}}}
Further solving this equation, we get
CrC0=K\dfrac{{{C_r}}}{{{C_0}}} = K where K is the dielectric constant of the medium.
This is the required ratio.
Since the dielectric constant is the ratio of permeability of a material to the permeability of free space, it is a unitless quantity.

Note: Capacitance is dependent on its geometry and this formula is applicable only for parallel plate capacitors. The units of any physical quantity can be easily found by substituting proper units in place of the physical quantities in a relation satisfied by the physical quantity whose units are desirable.