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Question

Mathematics Question on The Fundamental Theorem of Arithmetic

Explain why 7×11×13+137 × 11 × 13 + 13 and 7×6×5×4×3×2×1+57 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers.

Answer

Numbers are of two types - prime and composite. Prime numbers can be divided by 11 and only itself, whereas composite numbers have factors other than 11 and itself.
It can be observed that
7×11×13+13=13×(7×11+1)7 × 11 × 13 + 13 = 13 × (7 × 11 + 1)
=13×(77+1)=13×78= 13 × (77 + 1) = 13 × 78
=13×13×6= 13 ×13 × 6
The given expression has 66 and 1313 as its factors. Therefore, it is a composite number.
7×6×5×4×3×2×1+57 × 6 × 5 × 4 × 3 × 2 × 1 + 5
=5×(7×6×4×3×2×1+1)= 5 ×(7 × 6 × 4 × 3 × 2 × 1 + 1)
=5×(1008+1)= 5 × (1008 + 1)
=5×1009= 5 ×1009
Since, 10091009 cannot be factorised further.

Therefore, the given expression has 55 and 10091009 as its factors. Hence, it is a composite number.