Question
Mathematics Question on Trigonometric Identities
∫exloga⋅exdx is equal to
A
(A) axlogae+c
B
(B) ax1+logea+c
C
(C) lae|x+c
D
(D) ∣aexlogeae+c
Answer
(D) ∣aexlogeae+c
Explanation
Solution
Explanation:
Let I=∫exloga⋅exdx=∫ax⋅exdx=∫(ae)xdx=(ae)xlogeae+c