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Question

Question: Choose the correct relation on the basis of Bohr's theory -...

Choose the correct relation on the basis of Bohr's theory -

A

velocity of electron \propto

B

frequency of revolution Z2n3\propto \frac{Z^2}{n^3}

C

radius of orbit n2Z\propto n^2 Z

D

force on electron Z3n4\propto \frac{Z^3}{n^4}

Answer

A, B, D

Explanation

Solution

Bohr's theory provides the following relations for hydrogen-like atoms:

  1. Radius of orbit (rnr_n): rn=n2a0Zr_n = \frac{n^2 a_0}{Z}, where a0a_0 is Bohr radius. Thus, rnn2Zr_n \propto \frac{n^2}{Z}. Option (C) rnn2Zr_n \propto n^2 Z is incorrect.

  2. Velocity of electron (vnv_n): vn=Ze22ϵ0nh=Zv0nv_n = \frac{Z e^2}{2 \epsilon_0 n h} = \frac{Z v_0}{n}, where v0v_0 is the velocity in the first Bohr orbit of H. Thus, vnZnv_n \propto \frac{Z}{n}. Option (A) is correct.

  3. Frequency of revolution (fnf_n): fn=vn2πrnf_n = \frac{v_n}{2\pi r_n}. Substituting vnZnv_n \propto \frac{Z}{n} and rnn2Zr_n \propto \frac{n^2}{Z}: fnZ/nn2/Z=Z2n3f_n \propto \frac{Z/n}{n^2/Z} = \frac{Z^2}{n^3}. Option (B) is correct.

  4. Force on electron (FF): This is the electrostatic force between the nucleus and the electron. F=k(Ze)ern2=kZe2rn2F = \frac{k (Ze) e}{r_n^2} = \frac{k Z e^2}{r_n^2}. Substituting rnn2Zr_n \propto \frac{n^2}{Z}: FZ(n2/Z)2=Zn4/Z2=Z3n4F \propto \frac{Z}{(n^2/Z)^2} = \frac{Z}{n^4/Z^2} = \frac{Z^3}{n^4}. Option (D) is correct.