Question

Excess pressure of one soap bubble is four times that of other. Then the ratio of volume of first bubble to second one is

• A. 0.086111111
• B. 64:01:00
• C. 4:01
• D. 1:02

Answer 1

Answer: (A)

0.086111111

Answer 2

$\Delta P = \frac{4T}{V^{\frac{1}{2}}}$