Question

Excess pressure of one soap bubble is four times more than the other. Then the ratio of volume of first bubble to another one is

• A. 1 : 64
• B. 1 : 4
• C. 64 : 1
• D. 1 : 2

Answer 1

Answer: (A)

1 : 64

Answer 2

$\therefore \frac { r _ { 2 } } { r _ { 1 } } = 4$ and $\frac { V _ { 1 } } { V _ { 2 } } = \left( \frac { r _ { 1 } } { r _ { 2 } } \right) ^ { 3 } = \frac { 1 } { 64 }$