Question

Excess of $PCl_5$ reacts with conc. $H_2SO_4$ giving

• A. chlorosulphonic acid
• B. thionyl chloride
• C. sulphuryl chloride
• D. sulphurous acid

Answer 1

Answer: (C)

sulphuryl chloride

Answer 2

$PC1_5$ reacts with cone $H_2SO_4$ to give sulphuryl chloride by replacing its hydroxyl groups with chlorine atoms.

$\underset{\text{sulphuric acid }}{SO _{2}( OH )_{2}}+2 PCl _{5} \longrightarrow \underset{\text{sulphuryl chloride }}{SO _{2} Cl _{2}} +2 POCl _{3}+2 HCl$