Excess of ammonia with sodium hypochloride solution in the p... | Chemistry | SolveeIt

Question

Excess of ammonia with sodium hypochloride solution in the presence of glue or gelatin gives

$\ce{NaNH2 }$

$\ce{NH2NH2 }$

$\ce{ N_2}$

$\ce{NH4Cl }$

Answer

$\ce{NH2NH2 }$

Explanation

Solution

Excess of ammonia $\left( NH _{3}\right)$ when reacts with sodium hypochlorite solution (NaOCl) in presence of glue or gelatin gives hydrazine $\left( NH _{2} \cdot NH _{2}\right)$ This process is known as Raschig process

$2 NH _{3}+ NaOCl \to N _{2} H _{4}+ NaCl + H _{2} O$

Addition of gelatin or glue suppress the side reaction by complexing with the metal ions and yield of hydrazine is increased.

Chemistry Question on p -Block Elements

Solution