Question

In the given arrangement, if all the capacitors are identical, then the potential difference across $C_5$ will be:

• A. 10 V
• B. 5 V
• C. 2.5 V
• D. 0 V

Answer 1

Answer: (D)

0 V

Answer 2

The circuit is a capacitive Wheatstone bridge. Since all capacitors are identical, the bridge is balanced because $C_1/C_2 = C_3/C_4 = C/C = 1$. In a balanced Wheatstone bridge, the potential difference between the bridge points (D and E) is zero. Therefore, the potential difference across $C_5$ is 0 V.