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Question

Question: Evaluate the limit x tends to zero \[\log (1 + 5x)\] whole divide by x....

Evaluate the limit x tends to zero log(1+5x)\log (1 + 5x) whole divide by x.

Explanation

Solution

Hint : Here the question in the form of word, so first we write in the actual form and then we will apply the limit to the function. When we apply the limit to the function, after applying the limit if we get the real number then we write as it is, otherwise if we get undetermined form then we apply the L'Hospital's rule.

Complete step-by-step answer :
Historically, Sir Issac Newton was the "inventor" of derivatives and Leibnitz introduced the concept of Limits. Limits and derivatives are extremely crucial concepts in Maths whose application is not only limited to Maths but are also present in other subjects like physics.
A limit is defined as a value that a function approaches as the input, and it produces some value. Limits are important in calculus and mathematical analysis and used to define integrals, derivatives, and continuity.
To express the limit of a function, we represent it as: limncf(n)=L\mathop {\lim }\limits_{n \to c} f\left( n \right) = L
Now consider the given question and it is written as
limx0log(1+5x)x\mathop {\lim }\limits_{x \to 0} \dfrac{{\log (1 + 5x)}}{x}
On applying the limit to the function, we have
log(1+5(0))0\Rightarrow \dfrac{{\log (1 + 5(0))}}{0}
On simplifying this we get
00\Rightarrow \dfrac{0}{0}
This is an undetermined form so we solve this by applying the L’hospital rule.
In mathematics, more specifically calculus, L'Hôpital's rule or L'Hospital's rule provides a technique to evaluate limits of indeterminate forms. It is denoted as
limxcf(x)g(x)\mathop {\lim }\limits_{x \to c} \dfrac{{f'(x)}}{{g'(x)}}
On applying the L’Hospital’s rule for the given limit function we have
limx011+5x.51\mathop { \Rightarrow \lim }\limits_{x \to 0} \dfrac{{\dfrac{1}{{1 + 5x}}.5}}{1}
On simplifying the above inequality we have
limx051+5x\mathop { \Rightarrow \lim }\limits_{x \to 0} \dfrac{5}{{1 + 5x}}
Now applying the limit that is as x tends to 0 we have
51+5(0)\Rightarrow \dfrac{5}{{1 + 5(0)}}
On simplifying we have
5\Rightarrow 5
Hence we have determined the limit for the given function.
So, the correct answer is “5”.

Note : Whenever we get the limit value of the function in the indeterminate form it is necessary to apply the L'Hospital's rule for the given function. While applying the L'Hospital's rule we have to differentiate each function with respect to x and again we apply the limit for the function which is differentiated.