Question
Mathematics Question on integral
Evaluate the integral: ∫12logxdx
A
(A) 2log2−1
B
(B) 2log2+1
C
(C) 2log2−3
D
(D) None of these
Answer
(A) 2log2−1
Explanation
Solution
Explanation:
Let's first integrate the expression under integral by parts.I=∫logxdx=∫(1)(logx)dxConsidering logx as the first function and 1 as the second function, we get:=(logx)∫1dx−∫[1x∫1dx]dx [∵∫f(x)g(x)dx=f(x)∫g(x)dx−∫[f′(x)∫g(x)dx]dx=(logx)x−x+CPutting the limits of the definite integral, we get:∫12logxdx=[x(logx)−x]12=(2log2−2)−(0−1)=2log2−1Hence, the correct option is (A).