Question

Evaluate the Given limit: $\lim_{x\rightarrow 1}4$ $\frac{4x-3}{x-2}$

Answer 1

$\lim_{x\rightarrow 1}4$ $\frac{4x-3}{x-2}$ = 4(4) +$\frac{3}{4-2}$ = 16 +$\frac{3}{2}$ = $\frac{19}{2}$