Question

Evaluate the Given limit: $\lim_{x\rightarrow 1}$ $\frac{ax^2+bx+c}{cx^2+bx+a}$ , a + b + c ≠0

Answer 1

∴\lim_{x\rightarrow 1}$$\frac{ax^2+bx+c}{cx^2+bx+a} = $\frac{a(1)^2+b(1)^2+c}{c(1)^2+b(1)+a}$
= $\frac{a+b+c}{a+b+c}$
=1 [a+b+c $\neq$ 0]