QuestionReportMathematics Question on LimitsEvaluate the Given limit: limx→0\lim_{x\rightarrow 0}limx→0 cos xπ−x\frac{cos\,x}{\pi-x}π−xcosxAnswerlimx→0\lim_{x\rightarrow 0}limx→0 cos xπ−x\frac{cos\,x}{\pi-x}π−xcosx = cos 0π−0\frac{cos\,0}{\pi-0}π−0cos0 = 1π\frac{1}{\pi}π1