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Question

Question: Evaluate \( {n^{th}} \) derivative of \( {e^{ax}} \) ....

Evaluate nth{n^{th}} derivative of eax{e^{ax}} .

Explanation

Solution

Before attempting this question, one should have prior knowledge about the concept of derivative and also remember to identity the pattern of differentiation of the given function and use ddxex=ex\dfrac{d}{{dx}}{e^x} = {e^x} , use this information to approach the solution.

Complete step-by-step answer:
Let y=eaxy = {e^{ax}}
Since, we have to find the nth{n^{{\text{th}}}} derivative of the above given function.
Let us differentiate the given function once with respect to x, we get
First derivative, y1=dydx{y_1} = \dfrac{{dy}}{{dx}}
y1=d(eax)dx{y_1} = \dfrac{{d\left( {{e^{ax}}} \right)}}{{dx}}
Since we know that ddxex=ex\dfrac{d}{{dx}}{e^x} = {e^x} and ddx(x)=1\dfrac{d}{{dx}}\left( x \right) = 1
y1=eaxddx(ax)=aeax{y_1} = {e^{ax}}\dfrac{d}{{dx}}\left( {ax} \right) = a{e^{ax}} (equation 1)
Now, let us differentiate the given function again with respect to x, we get
Second derivative, y2=dy1dx{y_2} = \dfrac{{d{y_1}}}{{dx}}
y2=ddx(aeax){y_2} = \dfrac{d}{{dx}}\left( {a{e^{ax}}} \right)
y2=aeaxddx(ax){y_2} = a{e^{ax}}\dfrac{d}{{dx}}\left( {ax} \right)
y2=a2eax{y_2} = {a^2}{e^{ax}} (equation 2)
Now, let us differentiate the given function again with respect to x, we get
Third derivative, y3=dy2dx{y_3} = \dfrac{{d{y_2}}}{{dx}}
y3=ddx(a2eax){y_3} = \dfrac{d}{{dx}}\left( {{a^2}{e^{ax}}} \right)
y3=a2eaxddx(ax){y_3} = {a^2}{e^{ax}}\dfrac{d}{{dx}}\left( {ax} \right)
y3=a3eax{y_3} = {a^3}{e^{ax}} (equation 3)
After observing equations (1), (2) and (3), we can say that these derivatives are following a specific pattern and according to this pattern we can write the nth{n^{{\text{th}}}} derivative of the given function as
yn=dndxn(eax)=aneax{y_n} = \dfrac{{{d^n}}}{{d{x^n}}}\left( {{e^{ax}}} \right) = {a^n}{e^{ax}} .

Note: In these types of problems, the given function is differentiated one by one in order to obtain a pattern which will considerably lead us to the final nth{n^{{\text{th}}}} derivative of the given function satisfying that particular pattern.