Question
Mathematics Question on integral
Evaluate : ∫sinx+3cosx1dx
A
logtan(2x)+C
B
−21logtan(2x+6π)+C
C
21logtan(2x+6π)+C
D
None of these
Answer
21logtan(2x+6π)+C
Explanation
Solution
Let I=∫sinx+3cosx1dx =21∫21sinx+23cosxdx ⇒I=21∫sin(x+3π)1dx=21∫cosec(x+3π)dx ⇒I=21logtan(2x+6π)+C