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Question

Mathematics Question on permutations and combinations

Evaluate (i)5!(ii)7!(i) 5! (ii) 7!

A

110,5030110,5030

B

120,5040 120, 5040

C

115,5020115, 5020

D

121,5000 121, 5000

Answer

120,5040 120, 5040

Explanation

Solution

(i) 5!=1×2×3×4×5=1205 ! = 1 \times 2 \times 3 \times 4 \times 5 = 120 (ii) 7!=1×2×3×4×5×6×7=50407! = 1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 = 5040