Question

Evaluate:
(i) 3-2
(ii) (-4)-2
(iii) $(\frac{1}{2})^{-5}$

Answer 1

(i) 3-2
3-2
$= \frac{1 }{3^2} = \frac{1}{9}\ [a^{-m} = \frac{1 }{ a^m}]$

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(ii) (-4)-2
(-4)-2 = $\frac{1 }{ (-4)^{2}} \ [a^{-m} = \frac{1 }{ a^m}]$

$= \frac{1 }{ (-4 × -4)}$

$= \frac{1 }{ 16}$

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(iii) $(\frac{1}{2})^{-5}$

$(\frac{1}{2})^{-5} = 25 = 2 × 2 × 2 × 2 × 2 = 32\ [a^{-m} = \frac{1 }{ a^m}]$