Question
Mathematics Question on Determinants
Evaluatex y x+yyx+yxx+yxy
Answer
Δ=x y x+yyx+yxx+yxy
Applying R1→R1+R2+R3, we have
Δ=2(x+y) 2(x+y) 2(x+y)yx+yxx+yxy
= 2(x+y)1 1 1yx+yxx+yxy
Applying C2→C2-C1 and C3→C3-C1, we have
Δ=2(x+y)1 0 0yxx−yx+yx−x
Expanding along R1, we have:
Δ=2(x+y)[-x2+y(x-y)]
=-2(x+y)(x2+y2-yx)
=-2(x3+y3)