Question
Mathematics Question on Determinants
Evaluate1 1\1xx+yxyyx+y
Answer
Δ=$$\begin{vmatrix} 1 & x & y\\\ 1 & x+y & y\\\1&x&x+y \end{vmatrix}
Applying R2→R2−R1 and R3→R3−R1,we have
Δ=$$\begin{vmatrix} 1 & x & y\\\ 0 & y & 0\\\0&0&x \end{vmatrix}
Expanding along C1,we have:
Δ=1(xy−0)=xy