Question
Mathematics Question on Laws of Exponents
Evaluate
- 2−4(8−1×53)
- (5−1×2−1)×6−1
Answer
(i) 2−4(8−1×53)
Since, a−m=am1,am÷an=am−n
2−4(8−1×53)
=81(24×53) [Since a−m=am1]
=23(24×53)
=24−3×53 [am ÷ an = am − n]
= 2 × 125
= 250
(ii) (5−1×2−1)×6−1
Since,am×bm=(ab)m,a−m=am1
(5−1×2−1)×6−1
=10−1×6−1
=(10×6)−1 [∵am×bm=(ab)m]
=(60)−1=601 [∵a−m=am1]