Question
Question: Ethylidene chloride can be prepared by the reaction of \[HCl\] and: A.Ethane B.Ethylene C.Ace...
Ethylidene chloride can be prepared by the reaction of HCl and:
A.Ethane
B.Ethylene
C.Acetylene
D.Ethylene glycol
Solution
In the question, we have given an incomplete reaction. So here we should know the preparation of Ethylidene chloride. So we can use the given options and then we will react to them HCl. If the product obtained from the reaction is Ethylidene chloride then that reaction will be considered as the preparation of Ethylidene chloride.
Complete step by step answer:
-First, we will understand the question properly. In the question, we have the product as Ethylidene chloride. We need to find the reactant which can react with HCl to give Ethylidene chloride.
-So, we will react to the compounds given in the question with Hydrochloric acid (HCl). So let’s start with the reactions one by one.
A.First, we will react with Ethane with HCl. There is no reaction here as alkanes do not directly give a reaction HCl.
B.Now we will react to Ethylene with HCl. It will undergo an electrophilic addition reaction so the product will be formed according to Markovnikov’s rule.
C.Now we will react Acetylene with HCl. The reaction will undergo electrophilic addition and the product will be formed according to Markovnikov’s rule.
D. Ethylene glycol does not react HCl directly. It reacts with an aldehyde in the presence of dry HCl to give cyclic acetal.
-Therefore, from the above reactions, we can conclude that acetylene on reaction with HCl gives ethylidene chloride.
-The product is formed according to Markovnikov’s rule in which halogen gets attached to the carbon atom with less number of the hydrogen atom.
Hence, the correct option is (C).
Note:
If the question HCl is given in excess then the product of a reaction in which Acetylene reacts HCl will be Ethylidene dichloride. Due to excess HCl, Ethylidene chloride will again undergo electrophilic addition and the product will be formed according to Markovnikov’s rule.