Question

Ethyl alcohol on oxidation with acidified ${K_2}C{r_2}{O_7}$ gives ethanal.
A. True
B. False

Answer 1

In chemistry, various chemicals react in different ways some react in a homogeneous way and some others react to form other compounds. The change in the colour of the compounds may mark the proceeding of the reaction. In other cases, the progress of the reaction is marked by the evolution of certain gases or the formation of certain compounds.

Complete answer:

One of the most important processes in chemistry is the process of oxidation in which the compound is treated with an oxygen donating group which in turn oxidises the compound by the addition of the oxygen atom and decreasing the number of electrons in the compound. If the compound gains electrons then it is reduced. Oxidation and reduction go hand in hand.
It is found by studies and b the observation of the reactions that the compound of ethyl alcohol on controlled oxidation with acidified ${K_2}C{r_2}{O_7}$ gives ethanal but when the same compound undergoes complete oxidation it results in the formation of ethanoic acid.
The reaction involved can be represented as follows:
$C{H_3}OH + [O]\xrightarrow[{dil.{H_2}S{O_4}}]{{{K_2}C{r_2}{O_7}}}C{H_3}CHO + [O]\xrightarrow[{dil.{H_2}S{O_4}}]{{{K_2}C{r_2}{O_7}}}C{H_3}COOH$
So, the above statement is true only if the compound oxidises in a controlled manner however is false in the case of full oxidation. Generally, when only the term oxidation is used we usually refer to full oxidation

So, the Statement is false.

Note:

The structure of the hydroxyl group is represented $R-O-H$.
According to the rules, the hydroxyl name refers to the $(OH)$ radical only, while the $- OH$ is named as a hydroxyl group.
The formation of the hydrogen bonds helps in the easy solubility of the compounds containing this group in polar solvents.