Question

Ethene when treated with $Br_{2}$ in the presence of $CCl_{4}$ which compound is formed.

• A. 1, 2-dibromoethane
• B. 1-bromo-2-chloroethane
• C. Both (1) and (2)
• D. 1, 1, 1-tribromoethane

Answer 1

Answer: (A)

1, 2-dibromoethane

Answer 2

$CH_{2} = CH_{2} + Br_{2}\overset{\quad CCl_{4}\quad}{\rightarrow}\underset{\begin{aligned} & \text{1, 2-dibromo } \\ & \text{ethane} \end{aligned}}{\underset{Br}{\underset{|}{CH_{2}}} - \underset{\underset{Br}{|}}{CH_{2}}}$