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Question: Ethanol, is the substance commonly called alcohol. The density of liquid alcohol is \(0.7893g\text{ ...

Ethanol, is the substance commonly called alcohol. The density of liquid alcohol is 0.7893g ml10.7893g\text{ m}{{\text{l}}^{-1}} 293K293K. If 1.21.2 moles of ethanol are needed for a particular experiment, what volume of ethanol should be measured out?
(a) 55 ml55\text{ ml}
(b) 58 ml58\text{ ml}
(c) 70 ml\text{70 ml}
(d) 79 ml\text{79 ml}

Explanation

Solution

First we have to find the mass of ethanol by using the formula as given mass=mole×molecular massgiven\text{ }mass=mole\times molecular\text{ }mass and after finding the mass we can easily calculate the volume of ethanol by applying the density formula as; density=massvolumedensity=\dfrac{mass}{volume}. Now solve it.

Complete answer:
First of all, let’s discuss ethanol. Ethanol is a member of the alcohol family and consists of two carbon atoms along with the -OH group and its common name is ethyl alcohol and has a high boiling point and is readily soluble in water. The chemical formula of ethanol is as CH3CH2OHC{{H}_{3}}C{{H}_{2}}OH.
Now considering the statement as;
We can find the volume of the ethanol by using the formula as;
density=massvolume volume=massdensity \begin{aligned} & density=\dfrac{mass}{volume} \\\ & volume=\dfrac{mass}{density} \\\ \end{aligned} (1)
First, we have to find the mass of the ethanol.
We have been moles of ethanol as 1.21.2 and
Molecular mass of ethanol i.e. C2H5OH=12×2+5+16+1=46g{{C}_{2}}{{H}_{5}}OH=12\times 2+5+16+1=46g
Then, we can find the mass of the ethanol by using the formula as;
mole=given massmolecular mass given mass=mole×molecular mass      =1.2× 46      =55.2 g \begin{aligned} & mole=\dfrac{given\text{ }mass}{molecular\text{ }mass} \\\ & given\text{ }mass=mole\times molecular\text{ }mass \\\ &\implies \text{ =1}\text{.2}\times \text{ 46} \\\ &\implies \text{ =55}\text{.2 g} \\\ \end{aligned}
And density of the ethanol is as0.7893g ml10.7893g\text{ m}{{\text{l}}^{-1}} (given)
Then, put these in equation (1),we get;
volume=massdensity      55.20.7893      70 ml \begin{aligned} & volume=\dfrac{mass}{density} \\\ &\implies \text{ }\dfrac{55.2}{0.7893} \\\ &\implies \text{ 70 ml} \\\ \end{aligned}

So, if the density of liquid alcohol is 0.7893g ml10.7893g\text{ m}{{\text{l}}^{-1}} 293K293K and If 1.21.2 moles of ethanol are needed for a particular experiment then the volume of ethanol measured is 70 ml70\text{ ml}.

Note: While doing the calculations, always keep in mind that the units of all should be same i.e. if density is in g ml1g\text{ }m{{l}^{-1}} , then the mass should also be in gram not in kilogram and the volume should be in milliliters and not in liters.