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Question

Question: Given $\eta = 6$ and the relation $\eta = \frac{1}{Sin^2\theta}$, find the value of $Sin^2\theta$....

Given η=6\eta = 6 and the relation η=1Sin2θ\eta = \frac{1}{Sin^2\theta}, find the value of Sin2θSin^2\theta.

Answer

16\frac{1}{6}

Explanation

Solution

Given η=6\eta = 6 and the relation η=1Sin2θ\eta = \frac{1}{Sin^2\theta}, substitute η=6\eta=6 into the equation to get 6=1Sin2θ6 = \frac{1}{Sin^2\theta}. Solving for Sin2θSin^2\theta yields Sin2θ=16Sin^2\theta = \frac{1}{6}.