Question

Equivalent weight of NH in the reaction, N $?$ NH is 17/3 while that of N is 28/6. Equivalent weight $\quad\quad \quad \quad \quad= \frac{Molecular\, weight}{Number\, of\, e^{-} lost or gained per mole}$

• A. If both assertion and reason are true and reason is the correct explanation of assertion
• B. If both assertion and reason are true but reason is not the correct explanation of assertion
• C. If assertion is true but reason is false
• D. If both assertion and reason are false

Answer 1

Answer: (A)

If both assertion and reason are true and reason is the correct explanation of assertion

Answer 2

$N^{^0}_{2}+6e^{-}\to2N^{3-}$ $\therefore\quad$ Equivalent weight of NH$_{3} = \frac{14+3}{3}=\frac{17}{3}$ $\quad\quad\quad\quad\quad\quad\quad\quad\quad$(Mol. wt. of NH$_{3}$ = 17) While, equivalent weight of N$_{2} = \frac{14\times2}{6}=\frac{28}{6}$