Question

Equivalent weight of $I_2$ in the reaction, ${I_2 + 5 Cl_2 + 6 H_2O -> 2 \, HIO_3 + 10 HCl}$ is

• A. M
• B. M/2
• C. M/65
• D. M/10

Answer 1

Answer: (D)

M/10

Answer 2

For the given reaction {\overset{\text{ 0}}{ {I_2 }}$->$\overset{\text{+5 }}{ {2IO}}^{-}_3} change in oxidation number of $I_2 = 10$ $\therefore$ E wt. of $I_2 = M/10$