Question

Equivalent resistance of the given network is

• A. 28
• B. 18
• C. 26
• D. 25

Answer 1

Answer: (B)

18

Answer 2

: Between points A and B all resistances are combined in series.

$\therefore R_{eq} = 3\Omega + 4\Omega + 5\Omega + 6\Omega = 18\Omega$