Equivalent mass of ( {K\_2Cr\_2O\_7}) in acidic solution is... | Chemistry | SolveeIt

Question

Equivalent mass of ${K_2Cr_2O_7}$ in acidic solution is equal to

molecular mass/2

molecular mass/4

molecular mass

molecular mass/6

Answer

molecular mass/6

Explanation

Solution

${$ \overset{\text{+6}}{ {C}} $r_2 O^{2-}_7 + 14 H^+ + 6e^- -> 2Cr^{3+} + 7H_2O }$
Total number of electrons gained = 6
Total change in oxidation number of Cr
???? = $2(+6) - 2(+3) = 6$
${Emass\, of \, K_2Cr_2O_7 = \frac{Mol.mass \, of \, K_2 Cr_2 O_7}{6} }$

Chemistry Question on d -and f -Block Elements

Solution