Question

Equivalent conductances of NaCl, HCl and CH₃COONa at infinite dilution are 126.45, 426.16 and $90Ohm^{- 1}cm^{2}$ respectively. The equivalent conductance of $CH_{3}COOH$ at infinite dilution would be

• A. $101.38Ohm^{- 1}cm^{2}$
• B. $253.62Ohm^{- 1}cm^{2}$
• C. $390.71ohm^{- 1}cm^{2}$
• D. $678.90ohm^{- 1}cm^{2}$

Answer 1

Answer: (C)

$390.71ohm^{- 1}cm^{2}$

Answer 2

$\Lambda^{0}(CH_{3}COOH) = \Lambda^{0}(CH_{3}COONa) + \Lambda^{0}(HCl) - \Lambda^{0}(NaCl)$ $\mathbf{= 91 + 426.16 - 126.45}$ $\mathbf{= 390.71O}\mathbf{h}\mathbf{m}^{\mathbf{-}\mathbf{1}}\mathbf{c}\mathbf{m}^{\mathbf{2}}\mathbf{.}$