Solveeit Logo

Question

Chemistry Question on Equilibrium

Equilibrium constant KpK_p for following reaction : MgCO3<=>MgO(S)+CO2(g){ MgCO_3 <=> MgO(S) + CO_2 (g)}

A

Kp=PCO2{ Kp = P_{CO_2}}

B

Kp=PCO2×PCO2×PMgOPMgCO3{ Kp = P_{CO_2} \times \frac{P_{CO_2} \times P_{MgO}}{P_{MgCO_3}}}

C

Kp=PCO2+PMgOPMgCO3{ Kp = \frac{P_{CO_2} + P_{MgO}}{P_{MgCO_3}}}

D

Kp=PMgCO3PCO2×PMgO{ Kp = \frac{P_{MgCO_3}}{P_{CO_2} \times P_{MgO}}}

Answer

Kp=PCO2{ Kp = P_{CO_2}}

Explanation

Solution

In heterogeneous system Kc,KpK_c,K_p is not based upon concentratrion or pressure of solid substance. Hence, at equilibrium their concentration or pressure are assumed as one .
  MgCO3(g)<=>MgO(s)+CO2(g)\therefore \; {MgCO_3(g) <=> MgO(s) + CO_2 (g) }
Kp=PCO2{K_p = P_{CO_2 }}