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Question

Question: Equilibrium constant for the reactions: \(2NO+O_{2}\leftrightarrows2NO_{2} is \ K_{c_{1}}\) \(NO...

Equilibrium constant for the reactions:
2NO+O22NO2is Kc12NO+O_{2}\leftrightarrows2NO_{2} is \ K_{c_{1}}
NO+SO22SO3+NOis Kc2NO+SO_{2}\leftrightarrows2SO_{3}+NO is \ K_{c_{2}}
2SO32SO2+O2is Kc32SO_{3}\leftrightarrows2SO_{2}+O_{2} is \ K_{c_{3}}
Then correct relation is:
A. Kc3=Kc1×Kc2K_{c_{3}}=K_{c_{1}}\times K_{c_{2}}
B. Kc3×Kc1×Kc22=1K_{c_{3}}\times K_{c_{1}}\times K^{2}_{c_{2}}=1
C. Kc3×Kc1×Kc2=1K_{c_{3}}\times K_{c_{1}}\times K_{c_{2}}=1
D. Kc3×Kc12×Kc2=1K_{c_{3}}\times K^{2}_{c_{1}}\times K_{c_{2}}=1

Explanation

Solution

Hint The equilibrium constant of a chemical reaction provides a better understanding of the relationship between reactants and the products when a reaction is at equilibrium.

Complete step by step answer:
- Equilibrium constant is basically the ratio of the products to the concentration of the reactions, where each reactant, as well as product, is raised to their respective stoichiometric coefficients.
- Equilibrium constant is used to determine chemical behaviour.
- For the given question, we will first write down the equilibrium constant for each of the given equations.

Kc1=[NO2]2[NO]2[O2]\begin{aligned} K_{c_{1}}=\dfrac{[NO_{2}]^{2}}{[NO]^{2}[O_{2}]} \end{aligned} Kc2=[NO][SO3][NO]2[SO2]\begin{aligned} K_{c_{2}}=\dfrac{ [NO][SO_{3}]}{[NO]^{2}[SO_{2}]} \end{aligned} Kc3=[O2][SO2]2[SO3]2\begin{aligned} K_{c_{3}}=\dfrac{[O_{2}][SO_{2}]^{2}}{[SO_{3}]^{2}} \end{aligned}

Now, on multiplying equilibrium constants of equation 1 and 3, we get

Kc1×Kc3=[NO2]2[NO]2[O2]×[O2][SO2]2[SO3]2\begin{aligned} K_{c_{1}}\times K_{c_{3}}=\dfrac{[NO_{2}]^{2}}{[NO]^{2}[O_{2}]}\times\dfrac{[O_{2}][SO_{2}]^{2}}{[SO_{3}]^{2}} \end{aligned}

Since

Kc1=[NO2]2[NO]2[O2]\begin{aligned} K_{c_{1}}=\dfrac{[NO_{2}]^{2}}{[NO]^{2}[O_{2}]} \end{aligned}

The equation will become

Kc1×Kc3=[NO2]2[SO2]2[NO]2[SO3]2\begin{aligned} K_{c_{1}}\times K_{c_{3}}=\dfrac{[NO_{2}]^{2}[SO_{2}]^{2}}{[NO]^{2}[SO_{3}]^{2}} \end{aligned}

So,

Kc1×Kc3×Kc22=1\begin{aligned} K_{c_{1}}\times K_{c_{3}}\times K^{2}_{c_{2}}=1 \end{aligned}

Therefore, the answer to the question is an option (B).

Additional information:
As we know that K is the ratio of certain amounts of products to their reactants at equilibrium, Q is the ratio at any particular point of time of the reaction. The spontaneity of the process is related to free energy change which is denoted by \Delta G.

Note: It is important for us to remember that there are several different types of equilibrium constants that provide us with the relationships between products and their reactants of a certain reaction.