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Question

Question: Equations of lines which passes through the points of intersection of the lines \(4 x - 3 y - 1 = 0...

Equations of lines which passes through the points of intersection of the lines 4x3y1=04 x - 3 y - 1 = 0 and 2x5y+3=02 x - 5 y + 3 = 0 and are equally inclined to the axes are.

A

y±x=0y \pm x = 0

B

y1=±1(x1)y - 1 = \pm 1 ( x - 1 )

C

x1=±2(y1)x - 1 = \pm 2 ( y - 1 )

D

None of these

Answer

y1=±1(x1)y - 1 = \pm 1 ( x - 1 )

Explanation

Solution

Slopes of the lines are 1 and –1

Since the point of intersection is (1, 1)

Hence the required equations are y1=±1(x1)y - 1 = \pm 1 ( x - 1 ).