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Question: Equations of diagonals of square formed by lines \(x = 0\) <img src="https://cdn.pureessence.tech/...

Equations of diagonals of square formed by lines x=0x = 0 x=1x = 1 and y=1y = 1are.

A

y=x,y+x=1y = x , y + x = 1

B

y=x,x+y=2y = x , x + y = 2

C

2y=x,y+x=132 y = x , y + x = \frac { 1 } { 3 }

D

y=2x,y+2x=1y = 2 x , y + 2 x = 1

Answer

y=x,y+x=1y = x , y + x = 1

Explanation

Solution

Co-ordinates of the vertices of the square are A(0,0)A ( 0,0 ) C(1,1)C ( 1,1 ) and D(0,1)D ( 0,1 ).

Now the equation of AC is y=xy = x and of BDB D is y1=11(x0)y - 1 = - \frac { 1 } { 1 } ( x - 0 ) x+y=1\Rightarrow x + y = 1 .