Question

Equation to the straight line cutting off an intercept 2 from the negative direction of the axis of y and inclined at 30⁰ to the positive direction of x, is

• A. $y + x - \sqrt { 3 } = 0$
• B. $y - x + 2 = 0$
• C. $y - \sqrt { 3 } x - 2 = 0$
• D. $\sqrt { 3 } y - x + 2 \sqrt { 3 } = 0$

Answer 1

Answer: (D)

$\sqrt { 3 } y - x + 2 \sqrt { 3 } = 0$

Answer 2

Let the equation of the straight line is $y = m x + c$.

Here $m = \tan 30 ^ { \circ } = \frac { 1 } { \sqrt { 3 } }$ and c = – 2

Hence, the required equation is $y = \frac { 1 } { \sqrt { 3 } } x - 2$

⇒ $\sqrt { 3 } y - x + 2 \sqrt { 3 } = 0$.