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Question

Question: Equation of the straight line making equal intercepts on the axes and passing through the point (2, ...

Equation of the straight line making equal intercepts on the axes and passing through the point (2, 4) is.

A

4xy4=04 x - y - 4 = 0

B

2x+y8=02 x + y - 8 = 0

C

x+y6=0x + y - 6 = 0

D

x+2y10=0x + 2 y - 10 = 0

Answer

x+y6=0x + y - 6 = 0

Explanation

Solution

Let the equation of line xa+yb=1\frac { x } { a } + \frac { y } { b } = 1

Given a=ba = b. So, equation of line is x+y=ax + y = a .....(i)

Line passes through (2, 4)

From equation (i), 2+4=a2 + 4 = a. So, a=6a = 6.

\therefore Equation of line x+y=6x + y = 6 i.e., x+y6=0x + y - 6 = 0.