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Question

Question: Equation of the perpendicular bisector of the line segment joining the points (7, 4) and (– 1, – 2),...

Equation of the perpendicular bisector of the line segment joining the points (7, 4) and (– 1, – 2), is.

A

4x3y=154 x - 3 y = 15

B

3x+4y=153 x + 4 y = 15

C

4x+3y=154 x + 3 y = 15

D

None of these

Answer

4x+3y=154 x + 3 y = 15

Explanation

Solution

Mid point (3,1)\equiv ( 3,1 )

Slope of perpendicular

Therefore the required equation is

4x+3y=4(3)+3(1)=154 x + 3 y = 4 ( 3 ) + 3 ( 1 ) = 15.