Question
Question: Equation of the perpendicular bisector of the line segment joining the points (7, 4) and (– 1, – 2),...
Equation of the perpendicular bisector of the line segment joining the points (7, 4) and (– 1, – 2), is.
A
4x−3y=15
B
3x+4y=15
C
4x+3y=15
D
None of these
Answer
4x+3y=15
Explanation
Solution
Mid point ≡(3,1)
Slope of perpendicular
Therefore the required equation is
4x+3y=4(3)+3(1)=15.