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Question: Equation of the parabola with its vertex at (1, 1)and focus (3, 1)is...

Equation of the parabola with its vertex at (1, 1)and focus

(3, 1)is

A

(x1)2=8(y1)(x - 1)^{2} = 8(y - 1)

B

(y1)2=8(x3)(y - 1)^{2} = 8(x - 3)

C

(y1)2=8(x1)(y - 1)^{2} = 8(x - 1)

D

(x3)2=8(y1)(x - 3)^{2} = 8(y - 1)

Answer

(y1)2=8(x1)(y - 1)^{2} = 8(x - 1)

Explanation

Solution

Given vertex of parabola (h,k)(1,1)(h,k) \equiv (1,1) and its focus

(a+h,k)(3,1)(a + h,k) \equiv (3,1) or a+h=3a + h = 3or a=2a = 2. We know that as the y- coordinates of vertex and focus are same, therefore axis of parabola is parallel to x-axis. Thus equation of the parabola is (yk)2=4a(xh)\mathbf{(y - k}\mathbf{)}^{\mathbf{2}}\mathbf{= 4a(x - h)} or (y1)2=4×2(x1)(y - 1)^{2} = 4 \times 2(x - 1) or

(y1)2=8(x1)(y - 1)^{2} = 8(x - 1)