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Question

Question: Equation of the line passing through points (a, b, c) and (a – b, b – c, c – a) is...

Equation of the line passing through points (a, b, c) and

(a – b, b – c, c – a) is

A

xaab,ybbc=zcca\frac{x - a}{a - b},\frac{y - b}{b - c} = \frac{z - c}{c - a}

B

xaa=ybb=zcc\frac{x - a}{a} = \frac{y - b}{b} = \frac{z - c}{c}

C

xab=ybc=zca\frac{x - a}{b} = \frac{y - b}{c} = \frac{z - c}{a}

D

xa2ab=yb2bc=zc2ca\frac{x - a}{2a - b} = \frac{y - b}{2b - c} = \frac{z - c}{2c - a}

Answer

xab=ybc=zca\frac{x - a}{b} = \frac{y - b}{c} = \frac{z - c}{a}

Explanation

Solution

Use formula xx1x2x1=yy1y2y1=zz1z2z1\frac{x - x_{1}}{x_{2} - x_{1}} = \frac{y - y_{1}}{y_{2} - y_{1}} = \frac{z - z_{1}}{z_{2} - z_{1}}